Test Index

JAMB Physics 2024 Paper

Question : 27

Total: 125

^{-1}

^{-1}

, cools from 75ºC to 35ºC

Solution:

Concept:

Heat lost by a cooling body depends on its mass, specific heat capacity, and temperature change.

Explanation:

Write the heat formula:

Q = mc\Delta\theta

Convert mass to kilograms:

m = 60\,\text{g} = 0.060\,\text{kg}

Calculate the temperature drop:

\Delta\theta = 75 - 35 = 40\,\text{K}

Substitute the values:

Q = 0.060 \times 460 \times 40

Compute the result:

Q = 1104\,\text{J}

So the heat given out is

1104\,\text{J}

Answer:

D. 1104J

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