JAMB Physics 2024 Paper

Concept:When the volume of a fixed mass of gas is constant, pressure is directly proportional to absolute temperature.This relationship is known as the pressure law or Gay-Lussac's law.Explanation:For a gas at constant volume, $\frac{P_1}{T_1} = \frac{P_2}{T_2}$.Given values are $P_1 = 40\, \text{mmHg}$, $T_1 = 298\, \text{K}$, and $T_2 = 348\, \text{K}$.Rearrange the formula to solve for the final pressure: $P_2 = \frac{P_1 T_2}{T_1}$.Substitute the known values into the equation: $P_2 = \frac{40 \times 348}{298}$.First, calculate the numerator: $40 \times 348 = 13920$.Then divide by the initial temperature: $P_2 = \frac{13920}{298} = 46.71\, \text{mmHg}$.Answer:The pressure exerted by the gas is $46.71\, \text{mmHg}$.Therefore, the correct option is B. 46.71mmHg.