Test Index

JAMB Physics 2024 Paper

Question : 38

Total: 125

The fourth overtone of a closed pipes is 900Hz, its fundamental frequency is

Solution:

Concept:

A closed pipe produces only odd harmonics.

Explanation:

Let the fundamental frequency be

f_0

For a closed pipe, the allowed frequencies are

f_0, 3f_0, 5f_0, 7f_0, 9f_0, \dots

The fourth overtone corresponds to

9f_0

Given

9f_0 = 900 \, \text{Hz}

So,

f_0 = \frac{900}{9} = 100 \, \text{Hz}

This matches option B.

Answer:

100 \, \text{Hz}

(Option B).

Go to Question:

Prev Question

Next Question