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JAMB Physics 2024 Paper

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Question : 42

Total: 125

A refrigerator uses 150W. If it is kept on for 336 hours non-stop, what is the energy consumed in KWh?

60.20KWh
50.40KWh
25.01KWh
30.20KWh

Solution:

Power = $\frac{\text{Energy consumed}}{\text{time}}$

150W → 0.150KW, time = 336hrs.

Energy consumed in KWh = 0.150 x 336 = 50.40KWh

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