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JAMB Physics 2024 Paper

Question : 80

Total: 125

The energy stored in the above capacitor is

Solution:

Concept:

The energy stored in a capacitor is given by the formula

E = \dfrac{1}{2}\dfrac{q^2}{C}

, where

q

is the charge and

C

is the capacitance.

Explanation:

From the circuit, the capacitance is

C = 2\,\mathrm{F}

and the charge stored is

q = 3\,\mathrm{C}

Substitute these values into the formula:

E = \frac{1}{2} \times \frac{(3)^2}{2}

E = \frac{1}{2} \times \frac{9}{2} = \frac{9}{4}

E = 2.25\,\mathrm{J}

This corresponds to option A.

Answer:

2.25\,\mathrm{J}

Option A.

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