Using P1P_1P1 V1V_1V1 = P2P_2P2 V2V_2V2
V2V_2V2 = P1×V2P2\; \frac{P_1 \times V_2}{P_2}P2P1×V2
V2V_2V2 = 105×204×105\; \frac{10^{5} \times 20}{4 \times 10^{5}}4×105105×20
V2V_2V2 = 5m3^{3}3