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JAMB Physics 2024 Paper

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Question : 86

Total: 125

At a pressure of 10

^{5}

^{-2}

, a gas has a volume of 20m

^{3}

. Calculate the volume at 4 x 10

^{5}

^{-2}

at constant temperature.

2m $^{3}$
3m $^{3}$
4m $^{3}$
5m $^{3}$

Solution:

Concept:

At constant temperature, Boyle's law states that

P_1V_1 = P_2V_2

.

Explanation:

Initial pressure,

P_1 = 10^{5}\ \mathrm{Nm^{-2}}

and initial volume,

V_1 = 20\ \mathrm{m^{3}}

.

New pressure,

P_2 = 4 \times 10^{5}\ \mathrm{Nm^{-2}}

.

Using

P_1V_1 = P_2V_2

, make

V_2

the subject:

V_2 = \frac{P_1V_1}{P_2}

Substitute the given values:

V_2 = \frac{10^{5} \times 20}{4 \times 10^{5}} = \frac{20}{4} = 5\ \mathrm{m^{3}}

Answer:

The new volume is

5\ \mathrm{m^{3}}

, which is option D.

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