JAMB Physics 2024 Paper

Concept:The force that pulls the body horizontally is only one component of the rope's tension. We resolve the tension into its horizontal component using the given angle.Explanation:Let the tension in the rope be $T$.The rope makes $30^\circ$ with the vertical.This means the horizontal component of the tension is $T\sin 30^\circ$.The effective horizontal force is $15\,N$.So, set the component equal to the given force: $T\sin 30^\circ = 15$.We know $\sin 30^\circ = 0.5$.Thus $T \times 0.5 = 15$.Divide both sides by $0.5$ to get $T = \frac{15}{0.5} = 30\,N$.The tension in the rope is therefore $30\,N$.Answer:$T = 30\,N$, so the correct option is A.