JAMB Physics 2024 Paper

density of methanol = 800kgm$^{-3}$ → 0.8gcm$^{-3}$

At equilibrium, the density of methanol = the density of liquid x

$\rho$ x h x g = $\rho$$_x$ x h$_x$ x g

0.8 x 7.1 = $\rho$$_x$ x 14.2

$\rho$$_x$ = $\;\frac{0.8 \times 7.1}{14.2}$ = 0.4gcm$^{-3}$

$\therefore$, the relative density of liquid x = 0.4

Relative density of X = $\;\frac{\;\text{density of liquid x}\;}{\;\text{density of methanol}\;}$ = $\;\frac{0.4}{0.8}$ = 0.5