Using the general gas equation;
P1×V1T1 = P2×V2T2
P1 = P, P2 = 2P, T1 = 27ºC → 300K, T2 = 127ºC → 400k,
V2 = P1×V1×T2T1×P2
V2 = P×V1×400300×2P = 2V13
ΔV = V1 - 2V13 = V13
Therefore, The volume decreases by 13 of the original volume.
