The number of sulphur atoms in 3.20g of SO₂(g)} is [O = 16.0;S = 32.0; Avogadro constant = 6.02 x 10²3}]

Correct Answer is : 3.01 x 1022

Correct Answer is : 3.01 x 1022

Test Index

WAEC Chemistry 2012 Paper

Question : 16

Total: 44

_{2(g)}

^{23}

]

Solution:

Concept:

Number of atoms is found by converting the given mass to moles, then using Avogadro's constant.

Explanation:

Molar mass of

\mathrm{SO_2} = 32.0 + 2(16.0) = 64.0\ \text{g mol}^{-1}

Moles of

\mathrm{SO_2}

3.20

\text{Moles of } \mathrm{SO_2} = \frac{3.20}{64.0} = 0.050

mol

Each

\mathrm{SO_2}

molecule contains exactly one sulphur atom.

So, moles of sulphur atoms

= 0.050

mol

Number of sulphur atoms

= 0.050 \times 6.02 \times 10^{23}

= 3.01 \times 10^{22}

atoms

Answer:

3.01 \times 10^{22}

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