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WAEC Chemistry 2012 Paper

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Question : 16

Total: 44

The number of sulphur atoms in 3.20g of SO

_{2(g)}

is [O = 16.0;S = 32.0; Avogadro constant = 6.02 x 10

^{23}

]

3.01 x 10²²
6.02 x 10²²
6.02 x10²³
1.20 x 10²⁴

Solution:

32g of sulphur = 64g / 6.02 x 10 $^{23}$ atoms of SO $_2$

xg of sulphur = 3.2g of SO $_2$

: 1.6g of sulphur is present in 3.2g / 3.01 x 10 $^{23}$ atoms of SO $_2$

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