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WAEC Chemistry 2012 Paper

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Question : 22

Total: 44

The volume occupied by 0.4 g of hydrogen gas at s.t.p. is [H = 1. 00; Molar volume at s.t.p. = 22.4 dm3]

2.24 dm³
4.48dm³
22.4dm³
44.8dm ³

Solution:

2g of H $_{2}$ = 22.4 dm $^{3}$

0.4g of H $_{2}$ = x,

x = $\frac{0.4 \times 22.4}{2}$ = 4.48dm $^{3}$

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