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WAEC Chemistry 2015 Paper

Question : 20

Total: 50

\rightarrow

[Molar Volume of gas = 22.4dm3

Solution:

$\frac{\text{volume}}{\text{molar volume}}$ = 0.05

1 mole of ethane produces 2 moles of carbon(iv)oxide

∴ 0.05 mole of ethane will produce x moles of carbon(iv)oxide

\frac{\text{volume}}{22.4}

= 0.05 X 2 X 22.4 = 2.24dm

_{3}

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