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WAEC Chemistry 2017 Paper

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Question : 25

Total: 50

The number of atoms present in 2.5moles of a triatomic gas is equivalent to [1mole =

6.02\times 10^{23}

]

$2.5\times 10^{23}$
$1.5\times 10^{23}$
$1.5\times 10^{24}$
$2.5\times 10^{24}$

Solution:

1 mole = $6.02 \times 10^{23}$

2.5 moles = $6.02 \times 10^{23} \times 2.5$

= $15.05 \times 10^{23} = 1.505 \times 10^{24}$

$\approx\text{eq} 1.5 \times 10^{24}$

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