Cu2++2e−toCu(s)
2×96500C=193000Cdeposits64gofCu
M∝It
Q=It=0.45A×1hr15mins
= 0.45×75×60 [converting the time to seconds]
Quantity of electricity passed = 2025C
193000Cto64gCu
1Cto64193000
2025Cto64193000×2025
=0.6715g≈eq0.67g