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WAEC Chemistry 2017 Paper

Question : 7

Total: 50

\mathrm{(NH_{4})_{2}CO_{3}}

is [O=16.0, N=14.0, C=12.0, H=1.0]

Solution:

This is same as asking for the molar mass of the compound

= $(2 \times 14.0) + (8 \times 1.0) + 12.0 + (16.0 \times 3)$

= 28.0+8.0+12.0+48.0 = 96.0g

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