Using
n = cv where n = no of mole, c = molar concentration(mol/dm3) and v = volume( dm3)
volume = 500cm3 = 0.5dm3, c = 0.005moldm−3
number of mole(n) = c x v = 0.5 X 0.005 = 0.0025mol.
but n = massmolarmass = 0.0025 = mass98 (where 98g/mol is the molar mass of H2SO4)
mass of H2SO4 = 0.0025 x 98 = 0.245g.
