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WAEC Chemistry 2018 Paper

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Question : 27

Total: 50

Consider the following reaction equation:

2\mathrm{HCl} + \mathrm{Ca}(\mathrm{OH})_{2} \to \mathrm{CaCl}_{2} + \mathrm{H}_{2}\mathrm{O}

. What is the volume of 0.1

\text{mol dm}^{-3}

HCl that would completely neutralize 25

\text{cm}^{3}

\text{mol dm}^{-3}

_{2}

?

150 $\text{cm}^{3}$
75 $\text{cm}^{3}$
30 $\text{cm}^{3}$
25 $\text{cm}^{3}$

Solution:

Using the formula, $\; \frac{C_A V_A}{C_B V_B} = \; \frac{N_A}{N_B}$ , we have

$\; \frac{0.1 \times V_A}{0.3 \times 25} = \; \frac{2}{1}$

$V_A = \; \frac{0.3 \times 25 \times 2}{0.1 \times 1}$

$V_A = 150\text{ cm}^{3}$

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