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WAEC Chemistry 2018 Paper

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Question : 35

Total: 50

The empirical formula of a compound containing 0.067mol Cu and 0.066mol O is [Cu = 63.5, O = 16]

$\mathrm{Cu}_2\mathrm{O}$
$\mathrm{CuO}$
$\mathrm{CuO}_2$
$\mathrm{CuO}_4$

Solution:

Cu : O

0.067 : 0.066

mole ratio $\;\frac{0.067}{0.066}$ : $\;\frac{0.066}{0.066}$

= 1 : 1

= CuO

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