Given the molecular formula, CH2\mathrm{CH}_2CH2.
The empirical formula will be (CH2)n(\mathrm{CH}_2)_n(CH2)n= 42
(12+(2×1))n=42(12+(2\times 1))n =42(12+(2×1))n=42
⇒ 14n=4214n =4214n=42
n = 3, hence the empirical formula is C3H6\mathrm{C}_3\mathrm{H}_6C3H6
