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WAEC Chemistry 2019 Paper
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© africaexams.com
Question : 22
Total: 50
consider the following reaction equation: 2Al(OH)
3
_3
3
+ 3H
2
_2
2
SO
4
_4
4
→
Al
2
_2
2
(SO4)
3
_3
3
(aq)+6H
2
_2
2
O. How many moles of tetraoxosulphate(vi)acid is needed to produce 0.5mol of aluminium tetraoxosulphate(vi)?
0.5
1.0
1.5
3.0
Validate
Solution:
Where 3mols of H2So4 = 1 mol of (Al2SO4)3
y mols of H2SO4 = 0.5 mol of (Al2SO4)3
Then cross multiply to have:
y =
3
×
0.5
1
\;\frac{3 \times 0.5}{1}
1
3
×
0.5
y = 1.5 moles
© africaexams.com
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