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WAEC Chemistry 2020 Paper
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© africaexams.com
Question : 28
Total: 49
5.0
cm
−
3
of
0.200
mol
dm
−
3
Na
2
CO
3
was diluted to
250
cm
−
3
solution, what would be the concentration of the resulting solution?
0.004 mol dm
−
3
0.020 mol dm
-3
0.200 mol dm
−
3
0.400 mol dm
−
3
Validate
Solution:
M
1
V
1
=
M
2
V
2
M
1
=
initial molarity
V
1
=
initial volume in liters
M
2
=
V
2
=
final volume in liters
0.200
×
5.00
=
M
2
×
250
M
2
=
1
∕
250
M
2
=
0.004
mol
dm
−
31
© africaexams.com
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