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WAEC Chemistry 2020 Paper

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Question : 36

Total: 49

How many moles of

\mathrm{H}_2\mathrm{SO}_4

50\ \mathrm{cm}^3

0.108\ \mathrm{mol}\ \mathrm{dm}^3

solution of the acid?

$5.4 \times 10$
$5.4 \times 10^{-3}$
$5.4 \times 10^{-2}$
$5.4 \times 10^{-1}$

Solution:

No. of moles

=\frac{\text{molarconc}\times\text{volume}}{1000}

No. of moles

=\frac{0.108 \times 50}{1000}

:

No. of moles

=0.0054

moles

=5.4 \times 10^{-3}

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