Concept:The indicator used decides how much
HCl is consumed in the titration of sodium carbonate.
Explanation:Student Y used phenolphthalein, which stops at the bicarbonate stage:
Na2CO3+HCl→NaHCO3+NaClHere, 1 mole of
Na2CO3 reacts with 1 mole of
HCl.
Student X used methyl orange, which allows complete neutralisation up to carbon dioxide:
NaHCO3+HCl→NaCl+CO2+H2OTaking both steps together, 1 mole of
Na2CO3 consumes 2 moles of
HCl.
Since both students used the same volume and concentration of sodium carbonate, the volume of
HCl used by X is double that used by Y.
Answer:C. the titer value obtained by X is twice that of Y