Concept:The sum of oxidation numbers of all atoms in a neutral compound is zero.Explanation:Let the oxidation number of chromium be x.The oxidation number of sodium is +1.The oxidation number of oxygen is −2.For Na2Cr2O7, the equation is:2(+1)+2x+7(−2)=0This simplifies to:2+2x−14=02x−12=02x=12x=+6Answer:The oxidation number of Chromium in Na2Cr2O7 is +6.Correct option: B. +6