Given V=xi^+yj^V = x\hat{i} + y\hat{j}V=xi^+yj^, the direction cosines are x∣V∣, y∣V∣\;\frac{x}{|V|},\;\frac{y}{|V|}∣V∣x,∣V∣y.
∣4i^−3j^∣=42+(−3)2=25=5|4\hat{i} - 3\hat{j}| = \sqrt{4^{2} + (-3)^{2}} = \sqrt{25} = 5∣4i^−3j^∣=42+(−3)2=25=5
Direction cosines = 45, −35\;\frac{4}{5},\;\frac{-3}{5}54,5−3.