Test Index

WAEC Further Mathematics 2010 Paper

Question : 38

Total: 40

2 + \sin\;(\theta + 25)

Solution:

$\sin\;\theta \leq 1$

i.e Maximum value of $\sin\;\theta \forall \theta = 1$ .

Therefore, $2 + \sin\;\theta \leq 2 + 1 = 3$

Go to Question:

Prev Question

Next Question