Concept:If (x−3) is a factor of a polynomial f(x), then by the Remainder Theorem, f(3)=0.Explanation:Let f(x)=2x2−2x+p.Since x−3 is a factor, substitute x=3 and set f(3)=0.f(3)=2(3)2−2(3)+p=02(9)−6+p=018−6+p=012+p=0p=−12Answer:The value of the constant is p=−12.Correct option: A. −12