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WAEC Further Mathematics 2011 Paper

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Question : 13

Total: 40

Find

\lim\limits_{x\to 3}\frac{x+3}{x^{2}-x-12}

-1
$\frac{-1}{7}$
$\frac{1}{7}$
1

Solution:

Concept:

Evaluate the limit by direct substitution, since the function is continuous at

x = 3

.

Explanation:

Substitute

x = 3

into the expression:

\lim\limits_{x\to 3}\frac{x+3}{x^{2}-x-12} = \frac{3+3}{3^{2}-3-12}

Simplify the numerator and denominator:

= \frac{6}{9 - 3 - 12} = \frac{6}{-6}

= -1

Answer:

-1

So the correct option is A. $-1$ .

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