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WAEC Further Mathematics 2011 Paper

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Question : 3

Total: 40

If

\log_{9} 3 + 2x = 1

, find x.

$-\frac{1}{2}$
$-\frac{1}{4}$
$\frac{1}{4}$
$\frac{1}{2}$

Solution:

$\log_{9} 3 = \log_{9} \left(9^{\frac{1}{2}}\right) = \frac{1}{2}\log_{9} 9 = \frac{1}{2}$

$\frac{1}{2} + 2x = 1 \implies 2x = \frac{1}{2}$

$x = \frac{1}{4}$

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