Solve 3x² + 4x + 1 > 0

Correct Answer is : x>−1,x>− 13x > -1, x > -\;1/3x>−1,x>−31

Correct Answer is : x>−1,x>− 13x > -1, x > -\;1/3x>−1,x>−31

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WAEC Further Mathematics 2011 Paper

Question : 8

Total: 40

Solve

3x^{2} + 4x + 1 > 0

Solution:

$3x^{2} + 4x + 1 > 0$

$3x^{2} + 3x + x + 1 > 0$

$3x(x + 1) + 1(x + 1) > 0$

$(3x + 1)(x + 1) > 0$

$3x + 1 > 0 \implies 3x > -1$

$x > -\;\frac{1}{3}$

$x + 1 > 0 \implies x > -1$

$x > -1, x > -\;\frac{1}{3}$

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