∫(3x2−2x−12)dx= 3x2+12+1− 2x1+12−12x\int (3x^{2} - 2x - 12) dx = \; \frac{3x^{2+1}}{2+1} - \; \frac{2x^{1+1}}{2} - 12x∫(3x2−2x−12)dx=2+13x2+1−22x1+1−12x
= x3−x2−12xx^{3} - x^{2} - 12xx3−x2−12x
(x3−x2−12x)∣−23=((33)−(32)−12(3))−((−23)−(−22)−12(−2))\left. (x^{3} - x^{2} - 12x) \right|_{-2}^{3} = \left( (3^{3}) - (3^{2}) - 12(3) \right) - \left( (-2^{3}) - (-2^{2}) - 12(-2) \right)(x3−x2−12x)−23=((33)−(32)−12(3))−((−23)−(−22)−12(−2))
= (27−9−36)−(−8−4+24)=−18−12=−30(27 - 9 - 36) - (-8 - 4 + 24) = -18 - 12 = -30(27−9−36)−(−8−4+24)=−18−12=−30
