WAEC Further Mathematics 2012 Paper

Step 1: Simplify the denominator
Start by simplifying the denominator. First, note that (x2n−3)‌

1

2

=x‌

2n−3

2

. Thus, the denominator becomes:
x2n+‌

5

2

⋅x‌

2n−3

2

Now, use the property of exponents that xa⋅xb=xa+b. Therefore, the denominator simplifies to:
x2n+‌

5

2

+‌

2n−3

2

=x2n+‌

5+2n−3

2

=x2n+‌

2n+2

2

=x2n+(n+1)=x3n+1
Step 2: Simplify the entire expression
Now, substitute the simplified denominator back into the original expression:
‌

x3n+1

x3n+1

Since the numerator and denominator are the same, the expression simplifies to:
1