log10( 13+ 14)+2log102+log10( 37)\log_{10} \left(\;\frac{1}{3} + \;\frac{1}{4}\right) + 2\log_{10} 2 + \log_{10}\left(\;\frac{3}{7}\right)log10(31+41)+2log102+log10(73)
13+ 14= 712\;\frac{1}{3} + \;\frac{1}{4} = \;\frac{7}{12}31+41=127
= log10( 712×22× 37)\log_{10}\left(\;\frac{7}{12} \times 2^{2} \times \;\frac{3}{7}\right)log10(127×22×73)
= log101=0\log_{10} 1 = 0log101=0