ddx(x2+xy−5)=d(x2)dx+d(xy)dx−d(5)dx=0\frac{d}{dx}(x^2 + xy - 5) = \frac{d(x^2)}{dx} + \frac{d(xy)}{dx} - \frac{d(5)}{dx} = 0dxd(x2+xy−5)=dxd(x2)+dxd(xy)−dxd(5)=0
= 2x+xdydx+y=02x + x\frac{dy}{dx} + y = 02x+xdxdy+y=0
⟹ xdydx=−(2x+y)\implies x\frac{dy}{dx} = -(2x + y)⟹xdxdy=−(2x+y)
dydx=−(2x+y)x\frac{dy}{dx} = \frac{-(2x + y)}{x}dxdy=x−(2x+y)
