∫02(8x−4x2) dx=( 8x1 + 12− 4x2+13)∣02\int\limits_{0}^{2} (8x - 4x^{2}) \, dx = \left( \; \frac{8x^{1\;+\;1}}{2} - \; \frac{4x^{2+1}}{3} \right)\big|_{0}^{2}0∫2(8x−4x2)dx=(28x1+1−34x2+1)02
= (4x2− 4x33)∣02\left(4x^{2} - \; \frac{4x^{3}}{3}\right) \big|_{0}^{2}(4x2−34x3)02
= (4(22)− 4(23)3)\left(4(2^2) - \; \frac{4(2^3)}{3}\right)(4(22)−34(23))
= 16− 323= 16316 - \; \frac{32}{3} = \; \frac{16}{3}16−332=316
