a 56×a −1n=1a^{\;\frac{5}{6}} \times a^{\;\frac{-1}{n}} = 1a65×an−1=1
⟹ a 56+ −1n=a0\implies a^{\;\frac{5}{6} + \;\frac{-1}{n}} = a^{0}⟹a65+n−1=a0
Equating bases, we have
56− 1n=0\;\frac{5}{6} - \;\frac{1}{n} = 065−n1=0
5n−66n=0\;\frac{5n - 6}{6n} = 06n5n−6=0
5n−6=0 ⟹ 5n=65n - 6 = 0 \implies 5n = 65n−6=0⟹5n=6
n= 65=1.20n = \;\frac{6}{5} = 1.20n=56=1.20
