Since f(3) = 0, then (x - 3) is a factor of f(x).
Dividing f(x) by (x - 3), we get 2x2+3x−22x^{2} + 3x - 22x2+3x−2.
2x2+3x−2=2x2−x+4x−22x^{2} + 3x - 2 = 2x^{2} - x + 4x - 22x2+3x−2=2x2−x+4x−2
x(2x−1)+2(2x−1)=(x+2)(2x−1)x(2x - 1) + 2(2x - 1) = (x + 2)(2x - 1)x(2x−1)+2(2x−1)=(x+2)(2x−1)
Therefore, f(x)=(x−3)(x+2)(2x−1)f(x) = (x - 3)(x + 2)(2x -1)f(x)=(x−3)(x+2)(2x−1)