h:x→2−12x−3h : x \to 2 - \frac{1}{2x-3}h:x→2−2x−31
h(x)=2(2x−3)−12x−3=4x−72x−3h(x) = \frac{2(2x-3)-1}{2x-3} = \frac{4x-7}{2x-3}h(x)=2x−32(2x−3)−1=2x−34x−7
Let x = h(y)
x=4y−72y−3x = \frac{4y-7}{2y-3}x=2y−34y−7
x(2y−3)=4y−7 ⟹ 2xy−4y=3x−7x(2y - 3) = 4y - 7 \implies 2xy - 4y = 3x - 7x(2y−3)=4y−7⟹2xy−4y=3x−7
y=3x−72x−4y = \frac{3x-7}{2x-4}y=2x−43x−7
h−1(x)=3x−72x−4h^{-1}(x) = \frac{3x-7}{2x-4}h−1(x)=2x−43x−7
