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WAEC Further Mathematics 2014 Paper

Question : 5

Total: 40

f(x) = 3x^{3} + 8x^{2} + 6x + k

f(2) = 1

, find the value of k.

Solution:

$f(x) = 3x^{3} + 8x^{2} + 6x + k$

$f(2) = 3(2^{3}) + 8(2^{2}) + 6(2) + k = 1$

$\implies 24 + 32 + 12 + k = 1$

$68 + k = 1 \therefore k = 1 - 68 = -67$

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