2cosx−1=0⇒2cosx=12\cos x - 1 = 0 \Rightarrow 2\cos x = 12cosx−1=0⇒2cosx=1
cosx=12\cos x = \frac{1}{2}cosx=21
x=cos−1(12)x = \cos^{-1} \left( \frac{1}{2} \right)x=cos−1(21)
= π3\frac{\pi}{3}3π = 5π3\frac{5\pi}{3}35π