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WAEC Further Mathematics 2015 Paper

Question : 37

Total: 40

The sum,

S_{n}

S_{n} = 2n^{2} - 5

. Find the 6th term.

Solution:

$S_{n} = 2n^{2} - 5$

$T_{n} = S_{n} - S_{n - 1}$

$T_{6} = S_{6} - S_{5}$

= $(2(6^{2} - 5) - (2(5^{2} - 5) = 62 - 40 = 22$

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