log3x=log93⇒log3x=log9912=12log99\log_{3} x = \log_{9} 3 \Rightarrow \log_{3} x = \log_{9} 9^{\frac{1}{2}} = \frac{1}{2}\log_{9} 9log3x=log93⇒log3x=log9921=21log99
log3x= 12\log_{3} x = \;\frac{1}{2}log3x=21
∴x=312\therefore x = 3^{\frac{1}{2}}∴x=321