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WAEC Further Mathematics 2016 Paper

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Question : 11

Total: 40

Solve for x in the equation

5^{x} \times 5^{x + 1} = 25

.

$-2$
$\;\frac{-1}{2}$
$\;\frac{1}{2}$
$2$

Solution:

$5^{x} \times 5^{x+1} = 25$

$5^{x} \times 5^{x+1} = 5^{2}$

$5^{x+x+1} = 5^{2}$ , equating powers,

$2x + 1 = 2 \implies 2x = 1$

$\therefore x = \;\frac{1}{2}$

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