tan(x+y)= tan x + tan y1 − tan xtan y\tan (x + y) = \; \frac{\tan\;x\;+\;\tan\;y}{1\;-\;\tan\;x\tan\;y}tan(x+y)=1−tanxtanytanx+tany
tanx= 512;tany= 34\tan x = \; \frac{5}{12} ; \tan y = \; \frac{3}{4}tanx=125;tany=43
tan(x+y)= 512 + 341 − ( 512× 34)\tan (x + y) = \; \frac{\;\frac{5}{12}\;+\;\frac{3}{4}}{1\;-\;\left(\;\frac{5}{12} \times \;\frac{3}{4}\right)}tan(x+y)=1−(125×43)125+43
= 14123348\frac{\;\frac{14}{12}}{\frac{33}{48}}48331214
= 5633\;\frac{56}{33}3356
