Variance (σ2)= ∑ (x − μ)2n\text{Variance } (\sigma^{2}) = \;\frac{\sum\;(x\;-\;\mu)^2}{n}Variance (σ2)=n∑(x−μ)2
The mean (μ)(\mu)(μ) of the data = 11 + 12 + 13 + 14 + 155= 655=13\;\frac{11\;+\;12\;+\;13\;+\;14\;+\;15}{5} = \;\frac{65}{5} = 13511+12+13+14+15=565=13
σ2= 105=2\sigma^{2} = \;\frac{10}{5} = 2σ2=510=2
