x2+x2y+3x−10y+3xy−10x^{2} + x^{2}y + 3x - 10y + 3xy -10x2+x2y+3x−10y+3xy−10
= x2+x2y+3x+3xy−10y−10=x2(1+y)+3x(1+y)−10(y+1)x^{2} + x^{2}y + 3x + 3xy - 10y - 10 = x^{2}(1 + y) + 3x(1 + y) - 10(y + 1)x2+x2y+3x+3xy−10y−10=x2(1+y)+3x(1+y)−10(y+1)
= (x2+3x−10)(y+1)(x^{2} + 3x - 10)(y + 1)(x2+3x−10)(y+1)
= (x2+3x−10)=x2−2x+5x−10(x^{2} + 3x - 10) = x^{2} - 2x + 5x - 10(x2+3x−10)=x2−2x+5x−10
= x(x−2)+5(x−2)=(x−2)(x+5)x(x - 2) + 5(x - 2) = (x - 2)(x +5)x(x−2)+5(x−2)=(x−2)(x+5)
∴x2+x2y+3x−10y+3xy−10=(x−2)(x+5)(y+1)∴ x^{2} + x^{2}y + 3x - 10y + 3xy -10 = (x - 2)(x + 5)(y + 1)∴x2+x2y+3x−10y+3xy−10=(x−2)(x+5)(y+1).
