WAEC Further Mathematics 2017 Paper

This can be done either by using quotient rule or by direct division of the equation, then differentiate.

$\; \frac{\;d}{\;d\;x} \left( \; \frac{5x^{3}\;+\;x^{2}}{x} \right)$

= $\; \frac{\;d}{\;d\;x} \left( \; \frac{5x^{3}}{x} + \; \frac{x^{2}}{x} \right)$

= $\; \frac{\;d}{\;d\;x} \left( 5x^{2} + x \right)$

= $10x + 1$