p=(5i−12j);∣p∣=52+(−12)2p = (5i - 12j); |p| = \sqrt{5^{2} + (-12)^{2}}p=(5i−12j);∣p∣=52+(−12)2
= 169=13\sqrt{169} = 13169=13
tanθ=−125=−2.4 ⟹ θ=−67.38∘\tan\theta = \frac{-12}{5} = -2.4 \implies \theta = -67.38^{\circ}tanθ=5−12=−2.4⟹θ=−67.38∘
Direction = 90∘−(−67.38∘)=157.38∘90^{\circ} - (-67.38^{\circ}) = 157.38^{\circ}90∘−(−67.38∘)=157.38∘
