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WAEC Further Mathematics 2017 Paper

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Question : 38

Total: 40

Given that

f(x) = 2x^{2} - 3

g(x) = x + 1

x \in R

. Find g o f(x).

$2(x^{2} - 1)$
$2x^{2} + 4x - 1$
$2x^{2} + 6x - 1$
$3(x^{2} - 1)$

Solution:

$f(x) = 2x^{2} - 3; g(x) = x + 1$

$g o f(x) = g(2x^{2} - 3)$

= $2x^{2} - 3 + 1 = 2x^{2} - 2 = 2(x^{2} - 1)$

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