WAEC Further Mathematics 2018 Paper

$\log_{2}(12x - 10) = 1 + \log_{2}(4x + 3)$

Recall, $1 = \log_{2}2$, so

$\log_{2}(12x - 10) = \log_{2}2 + \log_{2}(4x + 3)$

= $\log_{2}(12x - 10) = \log_{2}(2(4x + 3))$

$\implies (12x - 10) = 2(4x + 3) \therefore 12x - 10 = 8x + 6$

$12x - 8x = 4x = 6 + 10 = 16 \implies x = 4$